The updated list of Solutions to level 3, level 4 and NYTimes Sudoku hard puzzle games:
#Nytimes sudoku hard how to#
More Sudoku hard puzzles you may like to solve and learn how to solve Instead, focus has been to create a breakthrough at the earliest. Unnecessary enumeration of possible digit subsets in empty cells is avoided to speed up the solution. This Sudoku game is a hard Sudoku puzzle that needed multiple breakthroughs by advanced Sudoku techniques. With 2 in R8C6, R3C6 9 by reduction - R3C4 2 by reduction - R6C4 9 by reduction - R6C5 2 by reduction - R9C4 4 by exception in C4 - R9C5 9 by exception in C5 - R9C7 1 by exception in whole game. With Cycle (2,9) in C4, DS in leftout two cells is - R7C4 3 by reduction of 4 in R7 - R7C2 1 by reduction - R9C2 3 by reduction - R7C7 9 by reduction of 2 in C7 from DS in R7 - R7C3 2 by reduction - R8C3 9 by reduction - R8C6 2 by reduction and exception in R8. R7C6 7 by scan for 7 in R8, C4, C5 - R7C2 3 by reduction - R9C2 7 by reduction - R6C6 5 by parallel digit scan for 5 on empty cells of C6 eliminating R8C6 for 5 by 5 in R8, eliminating R3C6 by 5 in R3 leaving the lone cell R8C6 5. R1C6 8 by scan for 8 in C5, R3 - R1C5 6 by exception in R1. R2C5 4 by DSA reduction of from DS in three cells of R2 - R2C8 8 by reduction, R2C6 3 by exception in R2 - R1C8 4 by reduction - R7C8 6 by exception.
Solution to the NYT Sudoku Hard 28th February: Final Stage 4: No more challenges left With 2 in R4C9, R1C9 1 by reduction - R9C9 5, R1C7 2, R1C3 3 all by reduction of 1 - R2C3 1 by reduction.Ī Cycle of (2,9) is formed in R3C4, R3C6 as well as in R3C4, R6C4. It reduces the possible digit subset DS for the rest three cells to - breakthrough R8C2 6 by reduction of from DS - R8C8 7 by reduction - R4C8 5 by reduction - R4C9 2 by reduction - R6C7 7 by reduction. Solution to the NYT Sudoku Hard 28th February Stage 3: Breakthrough by DSAįirst valid cell is by scan: R3C2 4 by scan for 4 in C3 - R3C8 3 by reduction.Ĭycle (1,3) in R1C3, R2C3 as the two digits left for the two cells left in the top left major square.īecause of this Cycle in C3, a second Cycle of (2,9) is formed in R7C3, R8C3 in C3 and in bottom left major square this time. R6C3 4 by scan for 4 in R4 - R4C2 9 by exception in left middle major square. These three DSs thus form a Cycle of (2,5,7) in right middle major major square reducing in R5C7 to R5C7 8 - R5C4 6 by reduction - R5C9 4 by reduction - R5C3 7 by reduction - R6C9 6 by reduction - R4C7 3 by exception in right middle major square. Now we'll have a special breakthrough by a combination of DSA and Cycles.Īs are locked in the Cycle (3,4,8) in C8, DS in R4C8 is reduced by from DS in right middle major square.ĭS in R4C9 is reduced by from DS and DS in R6C7 is reduced by from . R8C9 3 by reduction of DS from Cycle (1,2,3,5) in C9 and in R8C9. With the last breakthrough of R5C2 5, R6C1 3 by reduction - R8C1 5 by reduction. Solution to the NYT Sudoku Hard, 28th February, 2021 Stage 2: Breakthrough by a combination of DSA and Cycles The only cell left in R5 for 5 is - R5C2 5. Now we are r eady for the breakthrough of R5C2 5 by parallel scan for 5 on empty cells of R5: cell eliminations for 5 in R5 are - R5C3 because of 5 in C3, R5C4 because of 5 in C4, R5C7 because of 5 in C7 and R5C9 because of 5 in Cycle (1,2,3,5) in C9. This gives us the next valid cell R5C6 1 by scan for 1 in R4, R6, C4.Īnalyzing the possible digits in neighborhood of top right major square identify the formation of a Cycle (1,2) in R1C7, R1C9 by double digit scan for in C8.īreakthrough by double digit scan, Cycle and parallel digit scan:įirst double digit cross scan for in R4 and C7 but not in right middle major square forms the Cycle (4,6) in R5C9, R6C9 in C9 at one go.Īs a result, a Cycle of (1,2,3,5) formed in rest of the cells in C9.
Next breakthrough is R4C1 1 by parallel scan for 1 empty cells of C1 eliminating R6C1 by 1 in R6 and eliminating R8C1 by 1 in R8. Step by step solution to the NYT Sudoku Hard 28th February, 2021 Stage 1: Breakthrough by Parallel digit scan and Double digit scanįirst valid cell R9C3 8 by row column scan for 8 in R7, R8, C2 - R3C1 8 by scan in C2, C3. The NYT Sudoku Hard, 28th February, 2021īefore going through the solution solve the puzzle first. It's a quick and easy solution to a hard Sudoku. How to solve NYT Sudoku hard Februexplains each breakthrough using advanced Sudoku techniques. How to solve NYT Sudoku Hard Februby advanced Sudoku techniques
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